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Home / Questions / Q 235
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Vandana
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Calculate the physical address given following 8086 register contents :1)SS=7698h SP=01FFh 2)CS=5526h IP=8874h

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6 Answers

  1. i am also finding the ans of this qsn how you wrote 8+F=7 plz tell

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  2. SS=76980
    SP=01FF
    01FF kaise 011F ho gaya
    9+1=10=A hota hai but apne B kyu likha
    Similarly 8+1=9 =9 he hona chahey
    Plz admin explain ?

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  4. Best Answer
    This answer was edited.

    Answer 1.
    The value of the stack segment register (SS) = 7698h
    The value of the stack pointer (SP) which is Offset = 01FFh
    Thus, Physical address of the top of the stack is:

    7 6 9 8 0
    + 0 1 F F
    7 6 B 7 F

    This calculation can be expressed as: Physical address = SS (hex) x 16 + SP (hex).
    Answer 2.
    The value of the code segment register (CS) = 5526h
    The value of the Instruction Pointer, holding address of the instruction = 8874h
    Physical address of the instruction
    Physical Address = CS (Hex) x 16 + IP

    5 5 2 6 0
    + 8 8 7 4
    5 D A D 4
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